Themes › Theme C Wave behaviour

C.4Standing waves and resonance

Pluck a guitar string or blow across a bottle and you hear a clear note. Waves bounce back and forth and add up to a standing wave that doesn't seem to travel at all. This topic explains how standing waves form, which notes a string or pipe can play, and why pushing something at just the right rate (resonance) can shatter a glass or shake a bridge. There is no additional HL content in C.4.

Knowledge and science

Nature of science

Patterns and trendsModelsObservationsGlobal impact of science

Patterns and trends. Pythagoras is said to have noticed that strings whose lengths are in simple ratios, such as 2 : 1 or 3 : 2, sound pleasant together. This was one of the first times that a pattern in nature was described with numbers.

Models. The same mathematical model, a whole number of half-wavelengths fitting into a fixed length, describes strings, pipes, microwaves in an oven and even electrons in atoms.

Observations. In the 1780s Ernst Chladni sprinkled sand on vibrating metal plates. The sand collected along the nodes and made beautiful patterns, so an invisible standing wave became something you could see.

Global impact. Engineers now design bridges, tall buildings and aircraft so that their natural frequencies are far from the frequencies of wind, traffic, footsteps and earthquakes.

ToK: questions to think about

  • Is music universal? Every culture makes music using strings, pipes or drums, and all of them rely on standing waves. Does physics explain why some notes sound good together, or is that cultural?
  • Can we know what we can't picture? Electrons in atoms are described by standing-wave patterns, and string theory imagines standing waves in many more dimensions than we can see. What role do reason and imagination play when observation is impossible?
  • Do words shape understanding? The IB says "first harmonic" rather than "fundamental", and musicians use different words again. Does it matter which name we use for the same idea?
  • Should we learn from failure? Some of what engineers know about resonance came from bridges that swayed dangerously. Is knowledge gained from accidents different from knowledge gained from planned experiments?

How do physics, NoS and ToK fit together? →

1. How standing waves form

A standing wave (also called a stationary wave) forms when two identical waves, with the same frequency, wavelength and amplitude, travel in opposite directions through the same medium and superpose (C.3). The usual way this happens is reflection: a wave travels to the end of a string or pipe, reflects, and meets the waves still arriving.

Three moments in time. In each, a wave travelling right and an identical wave travelling left are drawn, with their sum. At the first moment the two waves are in step and the sum has double the amplitude. An eighth of a period later the sum is smaller but its zero points have not moved. A quarter of a period later the two waves cancel and the sum is flat. The zero points of the sum stay in the same places throughout. t = 0t = T/8t = T/4
Wave travelling right, identical wave travelling left (dashed) and their sum (black), at three moments. The sum grows and shrinks, but its zero points stay put: it doesn't travel.

Compared with a travelling wave:

Travelling waveStanding wave
Energytransferred in the direction of travelno net transfer: the two waves carry equal energy in opposite directions, so energy is stored in the oscillating medium
Amplitudethe same for every pointvaries with position: zero at nodes, maximum at antinodes
Phasechanges steadily along the waveall points between two neighbouring nodes are in phase; points either side of a node are in antiphase ($\pi$ apart)
Wave profilemoves along at speed $v$stays in the same place; it just grows, shrinks and flips
Frequencyevery point oscillates at the same frequency (except nodes, which don't move)

2. Nodes, antinodes, amplitude and phase

A standing wave with three loops, drawn at several moments: at maximum displacement in each direction and at half that. Nodes, labelled N, are where the string never moves. Antinodes, labelled A, are at the middle of each loop. The distance from one node to the next is half a wavelength. NNNN AAA λ/2
The string at several moments. Solid and dashed blue: the two extreme positions, half a period apart. Nodes (N) never move; antinodes (A) have the largest amplitude.

Phase: all the points in one loop move up together and down together, so they are in phase, even though their amplitudes are different. The neighbouring loop is always doing the opposite. So two points in neighbouring loops are in antiphase, with a phase difference of $\pi$ (180°).

Energy: every point oscillates at the same frequency, but with a different amplitude. Since the energy of an oscillation depends on its amplitude squared (C.1), points near antinodes have the most energy and nodes have none.

3. Standing waves on strings

A string can only vibrate in patterns that fit its boundary conditions, which describe what happens at the two ends:

Each pattern that fits is called a harmonic. The one with the lowest frequency is the first harmonic. The IB uses "first, second, third harmonic" and does not use the words "fundamental" or "overtone".

Both ends fixed

A string fixed at both ends, vibrating in its first three harmonics. First harmonic: one loop, so the length is half a wavelength. Second harmonic: two loops, so the length is one wavelength. Third harmonic: three loops, so the length is one and a half wavelengths. 1st harmonic: L = λ/2 2nd harmonic: L = λ 3rd harmonic: L = 3λ/2
A string of length $L$ fixed at both ends. Each harmonic adds one more loop (half-wavelength).

A whole number of half-wavelengths must fit into the length $L$. For the $n$th harmonic:

$$L = n\,\frac{\lambda_n}{2} \quad\Rightarrow\quad \lambda_n = \frac{2L}{n}$$ $$f_n = \frac{v}{\lambda_n} = \frac{nv}{2L} = n f_1 \qquad (n = 1, 2, 3, \ldots)$$

All harmonics are possible. These formulas are not in the data booklet: work them out from a sketch.

The wave speed $v$ on a string depends on its tension and on its mass per unit length. A tighter or lighter string carries faster waves and so plays higher notes. That's how a guitarist tunes a string, and why the thickest strings play the lowest notes.

Both ends free (antinodes at both ends) gives exactly the same wavelengths and frequencies, with the nodes and antinodes swapped over.

One end fixed, one end free

A string fixed at the left end and free at the right end. First harmonic: a quarter of a wavelength fits in the length. Next possible pattern, the third harmonic: three quarters of a wavelength. Then the fifth harmonic: five quarters of a wavelength. There is a node at the fixed end and an antinode at the free end every time. 1st harmonic: L = λ/4 3rd harmonic: L = 3λ/4 5th harmonic: L = 5λ/4
Fixed end on the left (node), free end on the right (antinode). Only odd numbers of quarter-wavelengths fit.

Now an odd number of quarter-wavelengths must fit into $L$, so only the odd harmonics exist:

$$L = n\,\frac{\lambda_n}{4} \quad\Rightarrow\quad \lambda_n = \frac{4L}{n}, \qquad f_n = \frac{nv}{4L} \qquad (n = 1, 3, 5, \ldots)$$

The harmonic number tells you how many times the first-harmonic frequency it is. So the pattern after the first harmonic is the third harmonic, with three times the frequency. There is no second harmonic.

Worked example: a guitar string

A guitar string is 0.65 m long between its fixed ends. Its first harmonic has a frequency of 110 Hz. Find (a) the speed of waves on the string, (b) the frequency and wavelength of the third harmonic and (c) the first-harmonic frequency when the guitarist presses the string onto a fret so that the vibrating length is 0.49 m.

(a) First harmonic: $\lambda_1 = 2L = 1.30$ m, so $v = f\lambda = 110 \times 1.30 = 143\ \text{m s}^{-1}$.

(b) $f_3 = 3f_1 = 330$ Hz.   $\lambda_3 = \dfrac{2L}{3} = 0.43$ m. (Check: $330 \times 0.433 = 143\ \text{m s}^{-1}$ ✓.)

(c) The tension and the string are unchanged, so $v$ is still 143 $\text{m s}^{-1}$:   $f_1 = \dfrac{v}{2L} = \dfrac{143}{2 \times 0.49} = 146$ Hz. A shorter string plays a higher note.

4. Standing waves in pipes

Sound in a pipe is a longitudinal wave: the air molecules oscillate back and forth along the pipe. We describe the patterns using displacement nodes and antinodes. (The IB does not require pressure nodes and antinodes, and it ignores the small "end correction" at open ends.)

Displacement patterns in three kinds of pipe, with the first two possible harmonics of each. Open at both ends: antinodes at both ends; first harmonic half a wavelength, then one wavelength. Closed at both ends: nodes at both ends; also half a wavelength, then one wavelength. Closed at one end and open at the other: node at the closed end, antinode at the open end; first harmonic a quarter of a wavelength, then three quarters. 1st harmonicnext harmonic open–openL = λ/2, then L = λ closed–closedL = λ/2, then L = λ closed–openL = λ/4, then L = 3λ/4
The curves show how far the air moves (displacement amplitude) at each point along the pipe, not the shape of anything. Thick lines are closed ends. Same ends: all harmonics. One closed, one open: odd harmonics only.

The pipes follow the same rules as strings:

Worked example: open or closed?

A pipe is 0.85 m long, and the speed of sound in air is 340 $\text{m s}^{-1}$. Find the first three possible frequencies when the pipe is (a) open at both ends and (b) closed at one end.

(a) $f_1 = \dfrac{v}{2L} = \dfrac{340}{1.70} = 200$ Hz. All harmonics are possible: 200, 400 and 600 Hz.

(b) $f_1 = \dfrac{v}{4L} = \dfrac{340}{3.40} = 100$ Hz. Only odd harmonics: 100, 300 and 500 Hz.

Closing one end halves the lowest frequency, so the note drops by an octave. It also removes the even harmonics, which changes the sound's character (its "timbre"). That's one reason why different instruments sound different even when they play the same note.

Worked example: measuring the speed of sound with a resonance tube

A tuning fork of frequency 512 Hz is held over the open top of a tube of water. The water level is slowly lowered. The sound is loudest when the air column is 16.5 cm long, and next loudest at 50.0 cm. Find the speed of sound.

Two tubes containing water, each with a tuning fork above the open top. In the first, the air column is short and holds a quarter of a wavelength. In the second, the water level is lower and the air column holds three quarters of a wavelength. The difference between the two lengths is half a wavelength. λ/4 3λ/4 water
The top is open (antinode) and the water surface is closed (node). The second resonance is half a wavelength longer than the first.

The tube acts as a pipe closed at the water surface. The two loudest positions are the first and third harmonics, $\frac{\lambda}{4}$ and $\frac{3\lambda}{4}$, so they differ by $\frac{\lambda}{2}$:

$\dfrac{\lambda}{2} = 50.0 - 16.5 = 33.5$ cm, so $\lambda = 0.670$ m and $v = f\lambda = 512 \times 0.670 = 343\ \text{m s}^{-1}$.

Using the difference between the two lengths is a good method: the antinode really sits slightly above the top of the tube, and subtracting cancels that error out. The frequency of the note stays at 512 Hz throughout, because the tuning fork sets it.

5. Summary of boundary conditions

EndsWavelength of $n$th harmonicHarmonics
node–node
string fixed at both ends; pipe closed at both ends
$\lambda_n = \dfrac{2L}{n}$all
antinode–antinode
string free at both ends; pipe open at both ends
$\lambda_n = \dfrac{2L}{n}$all
node–antinode
string with one free end; pipe closed at one end
$\lambda_n = \dfrac{4L}{n}$odd only

In every case, $f_n = \dfrac{v}{\lambda_n}$. If you forget a formula, sketch the pattern, count the quarter- or half-wavelengths, and work it out.

6. Natural frequency and resonance

Any object that can oscillate has a natural frequency $f_0$: the frequency at which it oscillates freely after being disturbed once and left alone. A swing, a mass on a spring, a wine glass and a bridge all have natural frequencies. Strings and pipes have many, one for each harmonic.

A driving force that pushes an object again and again at a driving frequency $f$ makes it oscillate at that frequency. This is a forced oscillation. Its amplitude depends on how close $f$ is to $f_0$:

Resonance happens when a system is driven at a frequency equal (or very close) to its natural frequency. The driver then transfers energy most efficiently, and the amplitude of oscillation is greatest.

Why doesn't the amplitude keep growing forever? Real systems always lose some energy, for example to friction, air resistance or sound. The amplitude grows until the energy lost in each cycle equals the energy supplied in each cycle. Then it stays steady. This is conservation of energy at work.

Pushing a child on a swing is the classic example. If you push once per swing, just as it starts to move away from you, a small push builds up a large swing. Push at a random rate and the swing barely moves.

7. Damping

Damping is the loss of energy from an oscillating system, which makes the amplitude decrease. It is caused by resistive forces such as friction, air resistance and drag in a liquid. The IB uses three levels of damping:

Displacement against time for an oscillator released from its maximum displacement, with three levels of damping. Light damping: it keeps oscillating with roughly the same period, but the amplitude slowly decreases. Critical damping: it returns to equilibrium in the shortest time without overshooting. Heavy damping: it returns to equilibrium very slowly, without overshooting. xt
Light damping, critical damping and heavy damping (black, dashed), each released from the same starting displacement.

How damping changes resonance

A graph of amplitude against driving frequency is called a resonance curve. Damping changes its shape:

Amplitude against driving frequency for three levels of damping. With light damping there is a tall, narrow peak at the natural frequency. With more damping the peak is lower and wider. With heavy damping the peak is low, broad and slightly to the left of the natural frequency. Af f₀ light
Resonance curves for light, moderate and heavy damping (black, dashed). The dashed vertical line marks the natural frequency $f_0$.

As the damping increases:

Damping does not change the natural frequency $f_0$, which depends only on the system itself (for example $m$ and $k$ for a mass on a spring). It changes how the system responds to a driving force.

At very low driving frequencies the amplitude is small but not zero: the system simply follows the slow pushes. At very high driving frequencies it can't keep up, and the amplitude falls towards zero.

8. Useful and destructive resonance

Useful resonance

Destructive resonance, and how it is reduced

A black-and-white film still of the Tacoma Narrows Bridge collapsing in 1940. A long section of the road deck is twisting and falling between the towers, with a cloud of debris below it.
The Tacoma Narrows Bridge, USA, collapsing on 7 November 1940, four months after it opened. A steady wind of about 64 km/h set the deck twisting with a growing amplitude until it broke. It is often given as an example of resonance, but engineers explain it as flutter: the twisting itself changed how the wind pushed on the deck, so the bridge kept feeding itself energy. Either way, too little damping let the oscillations grow. Film still: Barney Elliott, Wikimedia Commons, public domain.

9. Common mistakes

10. Check your understanding

Two points on a standing wave are in neighbouring loops. What is the phase difference between them?

$\pi$ radians (180°). They are in antiphase: when one moves up, the other moves down. Any two points in the same loop are in phase.

A string fixed at both ends has nodes 0.20 m apart when vibrating in its fourth harmonic. How long is the string, and what is the wavelength?

Node to node is half a wavelength, so $\lambda = 0.40$ m. The fourth harmonic has four loops, so $L = 4 \times 0.20 = 0.80$ m.

A pipe closed at one end has a first harmonic of 150 Hz. What are the next two frequencies at which it resonates?

Only odd harmonics are possible: 450 Hz (third harmonic) and 750 Hz (fifth harmonic). There is no resonance at 300 Hz.

Why are car shock absorbers designed to be critically damped?

After a bump, the car returns to its normal position as quickly as possible without bouncing up and down. With light damping it would keep bouncing; with heavy damping it would take a long time to settle, so the next bump would arrive before it recovered.

A system is driven at its natural frequency. Why does its amplitude stop increasing after a while?

The energy lost each cycle (to friction, air resistance and so on) increases as the amplitude grows. The amplitude stops increasing when the energy lost each cycle equals the energy supplied by the driver each cycle.

Practise C.4 questions